The angle of depression of a car parked on the road from the top of a 150 m high tower is 30°. The distance of the car from the tower (in metres) is

`(A) 50sqrt3`

`(B) 150sqrt 3`

`(C) 150sqrt2`

`(D) 75`

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#### Solution

Correct answer: A

Let AB be the tower and BC be distance between tower and car. Let θ be the angle of depression of the car.

According to the given information,

`In triangleABC,`

`tan theta =`

`BC=150/sqrt3=(150sqrt3)/3=50sqrt3`

Hence, distance between the tower and car is `50 sqrt3`

.

Concept: Heights and Distances

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